-8x^2+64x+1024=0

Solution for -8x^2+64x+1024=0 equation:

-8x^2+64x+1024=0

a = -8; b = 64; c = +1024;
Δ = b2-4ac
Δ = 642-4·(-8)·1024
Δ = 36864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36864}=192$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-192}{2*-8}=\frac{-256}{-16}
=+16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+192}{2*-8}=\frac{128}{-16}
=-8
$